What is the center of mass if square D is placed on top of square B?

AI Thread Summary
The discussion focuses on calculating the center of mass for a configuration of four equal-mass squares, specifically when square D is moved on top of square B. The proposed solution uses the center of mass formula, yielding xcm of -20 cm and ycm of 20 cm. Participants confirm the calculations appear correct, indicating agreement on the method used. The conversation emphasizes the importance of proper placement and mass distribution in determining the center of mass. Overall, the calculations and reasoning are validated by the forum members.
oceans93
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We have four squares that make up one big square. Square A is located at the top right corner, square B at the top left corner, square C at the bottom left corner, and square D at the bottom right corner. All these squares have equal masses, and the length of each square is 80 cm. What is the center of mass of the figure if square D is removed and placed on top of square B?
My solution is xcm= ((m1x1)+(m2x2)+(m3x3))/(m1+m2+m3)
m(-40+40+(2*-40))/4m
=-80/4=-20cm

ycm= m(40-40+(2*40))/4m
=80/4=20cm

Is this correct? Thank u
 
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oceans93 said:
My solution is xcm= ((m1x1)+(m2x2)+(m3x3))/(m1+m2+m3)
m(-40+40+(2*-40))/4m
=-80/4=-20cm

ycm= m(40-40+(2*40))/4m
=80/4=20cm

Is this correct? Thank u

looks good! :biggrin:
 
Even i guess its right
 

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