What is the change in entropy when mixing water and alcohol?

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The discussion revolves around calculating the change in entropy when mixing water and alcohol at different temperatures. The user initially calculates the final temperature and entropy change but arrives at an incorrect value, prompting a request for assistance. Suggestions include ensuring proper unit conversions for specific heat capacities and temperatures, as well as clarifying the correct temperature scale to use. The importance of accurate unit handling in thermodynamic calculations is emphasized. The conversation highlights the complexity of entropy calculations in mixed systems.
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Homework Statement



0.5 kg of water at a temperature of 5.6 oC is mixed with 1.3 kg of alcohol at 65.9 oC. They come to equilibrium. What is the change in entropy (in J/K) of the system when the two liquids are mixed?

Hint:
The specific heat capacity for water is 1 kcal/kgoC = 4186 J/(kgoC), and for alcohol it is 0.58 kcal/kgoC = 2430 J/kgoC.

2. The attempt at a solution

I calculate Tf = [m1c1T1+m2c2T2] / [(m1c1) + (m2c2)] = 41.87*C

then Delta S = m1c1 ln(Tf/T1) + m2c2 ln (Tf/T2) = 2778 J/C

Then I convert to J/K which is divide it by 274.15 = 10.13 J/K = INCORRECT!

This is a messy problem. Please help!
 
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Try Cp(water)=4.186 J/g-k and Cp(alcohol)=2.4 J/g-K. Convert temperatures to K and mass to grams. I assume your equations are accurate and the problem is related to units.
 
RTW69 said:
Try Cp(water)=4.186 J/g-k and Cp(alcohol)=2.4 J/g-K. Convert temperatures to K and mass to grams. I assume your equations are accurate and the problem is related to units.

Should I take 1 C = 274.15 K or 273 K?
 
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