What is the Charge and Error in a Parallel Plate Capacitor?

AI Thread Summary
To calculate the charge on a parallel plate capacitor, the formula Q = C * V is used, where C is capacitance and V is the potential difference. For a capacitor with C = 8.5±1 μF and V = 4.5±0.4 Volts, the charge can be determined by multiplying these values. The error in the charge can be calculated using the formula for propagation of uncertainty, which states that the relative errors in multiplication are additive. This means that the percentage errors in capacitance and voltage should be summed to find the total error in the charge. Understanding these calculations is essential for accurately determining the charge and its associated error in capacitors.
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A capacitor with capacitance of C = 8.5±1 μF has a potential difference of V = 4.5±0.4 Volts. What are the charge on the capacitor and the error in this value, in μC?

To find charge I just use Q = C*V correct? And how do I calculate the error?

Thank you!
 
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For s=ab
\frac{\delta s }{s}= \frac{\delta a}{a} + \frac{\delta b}{b}

Where \delta s is the error in s and similiarly for a and b.
 
Another way to say that is that for multiplying and dividing, the % errors in quantities are added.
 
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