What is the Charge of the Larger Sphere in Electrostatic Equilibrium?

  • Thread starter Thread starter conov3
  • Start date Start date
  • Tags Tags
    Charge Sphere
AI Thread Summary
In the discussion about the charge of two connected conducting spheres in electrostatic equilibrium, the smaller sphere with a diameter of 2.0 cm has a charge of 3.0 nC. The larger sphere, with a diameter of 9.0 cm, is calculated to have a charge of 13.5 nC based on the ratio of their diameters. The validity of this calculation hinges on understanding the formula for the potential at the surface of a charged conducting sphere. Participants confirm the correctness of the result while emphasizing the need to verify the underlying principles. The discussion highlights the relationship between the sizes of the spheres and their respective charges in electrostatic equilibrium.
conov3
Messages
33
Reaction score
0

Homework Statement



Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger sphere?

Homework Equations



?

The Attempt at a Solution



2/3=9/x
x=13.5nC? Am i able to use this rule to find the charge
 
Physics news on Phys.org
conov3 said:

Homework Statement



Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger sphere?

Homework Equations



?

The Attempt at a Solution



2/3=9/x
x=13.5nC? Am i able to use this rule to find the charge

Your result is correct.

You should verify that your 'rule' is valid. What is the formula for the potential at the surface of a charged conducting sphere?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Electric field problem — Changing the charge on two spheres
Replies
3
Views
1K
Charge rearrangement on conducting spheres
Replies
21
Views
4K
Find charge inner/hollow sphere
Replies
2
Views
2K
Point charge with very thin metal sheet along a spherical surface
Replies
21
Views
2K
Charged sphere and charged conducting shell
Replies
9
Views
3K
How Do Charges Distribute Between Concentric Spheres When Connected by a Wire?
Replies
3
Views
2K
Work done by moving charge from one sphere to another?
Replies
8
Views
3K
Determine the net charge of sphere C
Replies
2
Views
1K
What is the net electrostatic force of the sphere at the origin?
Replies
3
Views
2K
Find the amount of work to move a particle from point A to B
Replies
4
Views
1K

Hot Threads

Recent Insights

Back
Top