What is the Charge on a Bead Accelerating in a Uniform Electric Field?

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SUMMARY

The discussion centers on calculating the charge of a bead with a mass of 1.0 g in a uniform electric field of 200,000 N/C, which accelerates upward at 20 m/s². The relevant equations include F = qE and F = mg, leading to the relationship Eq - mg = ma. By applying Newton's second law, participants clarify how to relate the forces acting on the bead to determine its charge effectively.

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Sarah88
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Homework Statement



A small charged bead has a mass of 1.0 g. It is held in a uniform electric field E= 200,000 N/C up. When the bead is released, it accelerates upward with an acceleration of 20 m/s^2. What is the charge on the bead?

Homework Equations


F= qE
F= mg
(possibly F= ma)


The Attempt at a Solution



I tried this problem multiple different ways including:
mg-Eq= 0
as well as Eq= ma

However, I wasn't sure how to relate the three force equations (mg, ma, Eq) together for this problem (because all seem relevant in this problem). Thank you!
 
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Welcome to PF!

Hi Sarah! Welcome to PF! :smile:
Sarah88 said:
I tried this problem multiple different ways including:
mg-Eq= 0
as well as Eq= ma

However, I wasn't sure how to relate the three force equations (mg, ma, Eq) together for this problem (because all seem relevant in this problem). Thank you!

Well, you're nearly there :wink:

as in almost all dynamics problems, just apply good ol' Newton's second law …

sum of forces = mass times acceleration …

what do you get? :smile:
 
Hi,
Thanks for the welcome to the forum :)

Well, the sum of forces equal to ma: Eq- mg (oppose each-other) = ma, it makes a lot more sense when you take into account Newton's second law. Thank you for your help! :)
 

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