What is the Coefficient of Friction for a Lab Using Spring Scales?

AI Thread Summary
The discussion focuses on calculating the coefficient of kinetic friction using spring scales, with a mass of 0.411 kg and a normal force of 4.0278 N. The average pull force is recorded at 0.46 N, leading to a frictional force of -0.46 N. The formula for the coefficient of friction (μk) is clarified as μk = Fk / N, resulting in a calculated value of -0.1142, which is incorrect as coefficients of friction cannot be negative. The negative value arises from the defined direction of forces, emphasizing the importance of consistent sign conventions in calculations. Understanding these principles is essential for accurate lab results.
timsmith98
Messages
6
Reaction score
0

Homework Statement


I'm having trouble finding the coefficient of kinetic friction for a lab using spring scales.
Mass=.411kg
Normal Force=4.0278
Average Pull Force=.46N
Frictional Force= -.46N

Homework Equations


μ k = Fk / N.

The Attempt at a Solution


μ k = -.46N/4.0278
μ k = -.1142
 
Physics news on Phys.org
I am not entirely sure what the variable in the last part meant, it may be better if you could use subscripts to distinguish the terms. What I can say is that the coefficient of friction--μ is equal to the quotient of Friction force and normal force. So:

(Force of friction)/(Normal force) = μ

Have fun with the lab.
 
The coefficient of friction isn't going to be negative. That's just due to the direction that you defined as +ve.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top