I have a homework question (due tomorrow) that I cannot figure out how to answer. It is:(adsbygoogle = window.adsbygoogle || []).push({});

This problem involves a single surface with a single unknown coefficient of kinetic friction that can be found. A box starting from rest, slides down along an incline a distance of 8.8 meters. The incline is at 35.5 degrees above the horizontal. After it reaches the bottom of the incline, it travels horizontally

17. meters. What is the coefficient of kinetic friction of the surface?

In class we derived an equation that I thought would work. I know that

W = Fd or mgh [h being dsin(zeta)] and that

Wtotal = Wgravity + Wfriction.

(I'm going to say that the distance on the incline is di and the distance on the horizontal is dh) So I end up with Wtotal = mgh(di) - Coefficient Fk(Normal force on the incline)di - Coefficient Fk(Normal force on the horizontal)dh which is:

Wtot = mg(di)sin(zeta) - Coefficient Fk(mg)di(cos)(zeta) - Coefficient Fk(mg)dh

Is this even the right equation and if so, how then do I solve for Coefficient Fk?:uhh:

I'm sorry that it's so hard to read.

Thanks very much.

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# Homework Help: What is the coefficient of kinetic friction of the surface?

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