What is the coefficient of static friction in this block and string setup?

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The problem involves a 4.0 kg block of wood on a table with a string connected to a 1.8 kg hanging mass. To find the coefficient of static friction, the net force on the block is zero, indicating that the tension in the string equals the force of static friction. The normal force acting on the block is equal to its weight, calculated as 39.2 N. By determining the gravitational force on the hanging mass, which provides the tension, the static friction can be calculated using the equation Fs = μFn. Understanding the balance of forces is essential for solving the problem effectively.
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Homework Statement




A 4.0 kg block of wood sits on a table. A string is tied to the wood,
running over a pulley and down to a hanging object. The greatest mass that can be
hung from the string without moving the block of wood is 1.8 kg. Calculate the coefficient
of static friction between the block of wood and the table.

4.0 kg and 1.8 kg- mass

Homework Equations



Fs=μFn

The Attempt at a Solution



so i assume the block isn't moving so fnet would be 0, fn=fg so 4.0(9.8) ---> 39.2

i don't have fs and mew so how am i supposed to solve this?
 
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There are 2 forces acting horizontally on the block on the table. One is the tension force that can be calculated by looking at the forces on the hanging mass.
 
It is always best to create a diagram and Net force equations for each individual object. You are right in that F=0 but this also tells you that whatever force is pulling at the block of wood, there is an equal and opposite force that stops it from moving. This is crucial piece of information for your problem.
 
so if i calculate fg=mg on the hanging mass, would the force of tension be the same as fg?
 
jjesiee said:
so if i calculate fg=mg on the hanging mass, would the force of tension be the same as fg?
Sure!
 
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Thread 'A cylinder connected to a hanging mass'
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