What is the complexity of calculating the potential of a cylinder?

AI Thread Summary
Calculating the potential of a cylinder involves integrating over cylindrical coordinates, with the potential expressed as an integral involving the charge density and distance from the point of interest. The complexity arises from the need to evaluate a challenging integral that combines multiple variables, leading to a cumbersome expression. There is uncertainty about the accuracy of the calculations, with indications that mistakes may have been made in the process. The integral ultimately results in a messy solution, reflecting the inherent difficulties in such calculations. Overall, the discussion highlights the intricate nature of this mathematical problem.
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Homework Statement


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Homework Equations

The Attempt at a Solution

The position of the point (where V is to calculated) on the z-axis would be ##u = z_0 + l/2##.So in cylindrical coords,

$$V(u) = \int_V {k \rho \over (s^2 + (u -z)^2)^{1/2}} dV = k \rho \int_0^L \int_0^{2\pi} \int_0^R {k \rho \over (s^2 + (u -z)^2)^{1/2} } \ ds\ d\phi\ dz \\= 2\pi k \rho \int_0^L (R^2 + (u -z)^2)^{1/2} - (u - z)\ dz =2\pi k \rho \left[\int_0^L (R^2 + (u-z)^2)^{1/2} dz - z_0L \right]$$

This integral is very complex and cubersome to calculate. I think I made a mistake some where.
 
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Your work looks good to me. The last integral does turn out to yield a messy answer.
 
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