What is the Connection Between the Hubble Constant and Scalar Field Dynamics?

nikhilb1997
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1. Homework Statement
If \phi is a usual field is it possible that
H\dot{\phi}=-\partial^2\phi/{\partial x^2}
Where H is the Hubble constant and the dot denotes time derivative

2. Homework Equations
H\dot{\phi}=-\partial^2\phi/{\partial x^2}

3. The Attempt at a Solution
I tried different ways but am not able to find the particular expression for Hubble constant used here.
 
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On a curved spacetime, the Klein-Gordon equation for a massless scalar field is ##\nabla^\mu \nabla_\mu \phi =0##. If the spacetime is of the FRW type, then there will be a term proportional to ##H\dot{\phi}##. You seem to have missed the ##\ddot{\phi}## term in your expression, so you might want to go through the exercise of working this out from first principles.
 
fzero said:
On a curved spacetime, the Klein-Gordon equation for a massless scalar field is ##\nabla^\mu \nabla_\mu \phi =0##. If the spacetime is of the FRW type, then there will be a term proportional to ##H\dot{\phi}##. You seem to have missed the ##\ddot{\phi}## term in your expression, so you might want to go through the exercise of working this out from first principles.

Thanks a lot. I did miss that term because this was the part i was confused about but i guess that was important too.
 
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