What is the Constant Angular Velocity of a Watch's Second Hand?

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The discussion centers on determining the constant angular velocity of a watch's second hand. It is established that the second hand completes one full revolution in one minute, leading to a calculation of angular velocity as 2π/60 radians per second. The confusion arises when considering angular acceleration, but it is clarified that the second hand maintains a constant angular velocity throughout its motion. The correct interpretation confirms that the angular displacement is indeed 2π radians in 60 seconds. Thus, the constant angular velocity remains 2π/60 radians per second.
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omega of the second hand??

Consider a second hand in the watch. What is the constqant angular velocity.
Logicaly, i would say it travels through 1 rev in 1 min so, it is 2∏/60
However, if we look it on the other way, it has angular acceleration
so theta= (w node + w final)/2 * t gives 2∏/30 .. Where is my mistake??
 
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ehabmozart said:
Consider a second hand in the watch. What is the constqant angular velocity.
Logicaly, i would say it travels through 1 rev in 1 min so, it is 2∏/60
OK.
However, if we look it on the other way, it has angular acceleration
What other way? The angular velocity is constant.
so theta= (w node + w final)/2 * t gives 2∏/30 .. Where is my mistake??
What are you solving for? Using this you'll find an angular displacement of 2π radians in 60 seconds.
 
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