What is the Correct Distance with Force from Both Sides?

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The discussion centers around calculating the distance traveled by an object subjected to two forces. The initial force of 10N acts on a 10 kg mass for 10 seconds, followed by a 20N force in the opposite direction for 5 seconds. One participant claims to have calculated a distance of 87.5m, while another suggests that the answer depends on whether the first force continues after 10 seconds, yielding a distance of 75m if it does not. The ambiguity in the problem statement regarding the duration of the first force's application is a key point of contention. Accurate calculations require clarity on the forces' durations and the application of relevant equations.
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Homework Statement
Force of 10N acts on a stationary object of mass 10 kg. after 10 second, a force of 20 N acts on it for 5 s in the opposite direction. what is the distance travelled by the object?
Relevant Equations
f=ma
I am getting distance 87.5m. Is this correct?
 
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Welcome to PF. :smile:

Please type your work into the forum so we can check it. Thank you.
 
TheMath_boy said:
Homework Statement:: Force of 10N acts on a stationary object of mass 10 kg. after 10 second, a force of 20 N acts on it for 5 s in the opposite direction. what is the distance traveled by the object?
Relevant Equations:: f=ma

I am getting distance 87.5m. Is this correct?
The question is ambiguous. Does the first force go away after the 10 seconds or continue? Have you quoted it verbatim?

Either way, I don't get your answer.
Now I do, thanks @Delta2
 
Last edited:
TheMath_boy said:
I am getting distance 87.5m. Is this correct?
I suggest you read the forum rules, which specifically state that you have to show your work, not just an answer.
 
haruspex said:
Either way, I don't get your answer.
I get 87.5m if i consider that the first force continues to be applied and 75m if it doesnt.
 
Delta2 said:
I get 87.5m if i consider that the first force continues to be applied and 75m if it doesnt.
Ahem, yes.
 

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