What is the Correct Distance with Force from Both Sides?

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SUMMARY

The discussion centers on calculating the distance traveled by an object subjected to two forces: an initial force of 10N acting on a 10 kg mass for 10 seconds, followed by a 20N force acting in the opposite direction for 5 seconds. The calculated distance is 87.5m if the first force continues to act throughout the entire duration; otherwise, the distance is 75m if the first force ceases after 10 seconds. The ambiguity in the problem statement regarding the duration of the first force's application leads to differing interpretations of the solution.

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TheMath_boy
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Homework Statement
Force of 10N acts on a stationary object of mass 10 kg. after 10 second, a force of 20 N acts on it for 5 s in the opposite direction. what is the distance travelled by the object?
Relevant Equations
f=ma
I am getting distance 87.5m. Is this correct?
 
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Welcome to PF. :smile:

Please type your work into the forum so we can check it. Thank you.
 
TheMath_boy said:
Homework Statement:: Force of 10N acts on a stationary object of mass 10 kg. after 10 second, a force of 20 N acts on it for 5 s in the opposite direction. what is the distance traveled by the object?
Relevant Equations:: f=ma

I am getting distance 87.5m. Is this correct?
The question is ambiguous. Does the first force go away after the 10 seconds or continue? Have you quoted it verbatim?

Either way, I don't get your answer.
Now I do, thanks @Delta2
 
Last edited:
TheMath_boy said:
I am getting distance 87.5m. Is this correct?
I suggest you read the forum rules, which specifically state that you have to show your work, not just an answer.
 
haruspex said:
Either way, I don't get your answer.
I get 87.5m if i consider that the first force continues to be applied and 75m if it doesnt.
 
Delta2 said:
I get 87.5m if i consider that the first force continues to be applied and 75m if it doesnt.
Ahem, yes.
 
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