What Is the Critical Angle for Light in a Submerged Fiber Optic Cable?

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The critical angle for light in a fiber optic cable submerged in water can be calculated using Snell's Law. Given the refractive indices, the formula sin(C) = n2/n1 applies, where n1 is the refractive index of the fiber optic (1.5) and n2 is that of water (1.33). This results in a critical angle of approximately 61.03 degrees. Understanding this angle is crucial for ensuring that light remains confined within the fiber optic cable. Proper application of these principles is essential for the successful completion of the paper.
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A fiber optic (n = 1.5) is submerged in water (n = 1.33). What is the critical angle for light to stay inside the cable?


i am so confuzed. this is the final question of my paper and i am stuck on a couple questions before this so it is obvious i would get this. i just need a start please.
 
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dev-hud said:
A fiber optic (n = 1.5) is submerged in water (n = 1.33). What is the critical angle for light to stay inside the cable?


i am so confuzed. this is the final question of my paper and i am stuck on a couple questions before this so it is obvious i would get this. i just need a start please.

sinC = 1/n
 

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