What is the current through each ideal diode in this circuit?

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SUMMARY

The discussion focuses on calculating the current through ideal diodes in a circuit with a 10kΩ resistor and various voltage sources. The calculations yield currents of 1.13 mA for the first diode, 0 mA for the second diode due to reverse bias, 1.43 mA for the third diode, and 0.13 mA for the fourth diode. Corrections were made regarding the voltage across the diode and resistor in the third calculation, confirming that the voltage should be 10V instead of 15V.

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Homework Statement



find current through each diode, suppose that they are ideal (use the second approach)

[PLAIN]http://img30.imageshack.us/img30/102/86772682.jpg R is 10kohms

The Attempt at a Solution



a) (12-0.7)/10k = 1.13 mA

b) 0 because diode will be open, actually i added up the two voltate sources and i have a voltage source of 16Volts where + is connected with diodes - and - is connected with diodes + so its reverse biased, hence current will be 0

c) i added up the voltage sources i have 10 volts and its not reversed biased diodes voltage source will be 0.7

hence

(15-0.7)/10k = 1.43 mA

d) added up voltage sources i had a source of 2 volts

hence

(2-0.7)/10000 = 0.13mA

am i correct?
 
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Yeah a,b and d are correct, but in (c), the voltage across diode and resistor is 10 v and not 15 v as you have put in the equation.
 
n.karthick said:
Yeah a,b and d are correct, but in (c), the voltage across diode and resistor is 10 v and not 15 v as you have put in the equation.

you are right, thanks a lot :))
 

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