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What is the current

  1. Nov 1, 2009 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    What is the current entering the node.

    3. The attempt at a solution

    P=IV -> 510/.470=1085V
    R(Inductor)=wL -> 2pi*60*1.25 = 471.24
    R(Resistor)=V/I -> 1085/0.47 = 2308.74
    R(Total)= sqrt(R(Resistor)^2+R(Inductor)^2) -> 2356.12
    V=sqrt(2)*V(RMS) -> 1534.42
    I=V/R -> 1534.42/2356.12 = 0.65A
  2. jcsd
  3. Nov 1, 2009 #2


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    Science Advisor

    P=IV -> 510/.470=1085V
    R(Inductor)=wL -> 2pi*60*1.25 = 471.24
    Reactance in OHMS
    R(Resistor)=V/I -> 1085/0.47 = 2308.74 OHMS
    R(Total)= sqrt(R(Resistor)^2+R(Inductor)^2) -> 2356.12
    You can't do this for parallel circuits. You have to work out the currents and then put them in the right angled triangle.

    Don't forget that reactance is the term for the impedance of inductors and capacitors, not resistance which is purely for resistors.
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