What is the degree of dissociation of N2O4 at 100°C and 1 atm?

[utkarshakash]

Homework Statement

Vapour density of N_2O_4 which dissociated according to the equation
N_2O_4(g) \Leftrightarrow 2NO_2(g) is 25.67 at 100°C and a pressure of 1 atm. Calculate the degree of dissociation and K_p for the reaction

Homework Equations

The Attempt at a Solution

\alpha = \frac{D_t-D_o}{D_o}

D_t = \frac{92}{2}
Plugging in the values does not yield desired answer.

 

[Borek]

Please elaborate on what you are doing. What are D_t and D₀? What is 92?

Is that the whole question? Either I am missing something or it can't be solved as given.

 

[Saitama]

Please elaborate on what you are doing. What are D_t and D₀? What is 92?

Is that the whole question? Either I am missing something or it can't be solved as given.

I suppose the OP directly posted the equations without showing how he/she has got it. If i remember correctly, Dt and Do are the theoretical and observed vapour density of a mixture at equilibrium. 92 is the molar mass of N2O4.

 

[utkarshakash]

I suppose the OP directly posted the equations without showing how he/she has got it. If i remember correctly, Dt and Do are the theoretical and observed vapour density of a mixture at equilibrium. 92 is the molar mass of N2O4.

Yes that's right. But the answer which I'm getting is wrong.