- #1
ace123
- 250
- 0
Find y' if y= ln( x^2 + y^2)
I thought this was just a regular natural log derivative combined with the chain rule.
So what I got was (2x + 2y)/ (x^2 + y^2)
But this wasn't the correct answer. So could someone help point out my mistake.
Thank you.
I thought this was just a regular natural log derivative combined with the chain rule.
So what I got was (2x + 2y)/ (x^2 + y^2)
But this wasn't the correct answer. So could someone help point out my mistake.
Thank you.