What is the diagram for a particle attached to 2 elastic light springs?

AI Thread Summary
A particle of mass 0.8 kg is attached to two identical elastic springs, each with a natural length of 1.6 m and a modulus of elasticity of 16 N, positioned between two points A and B that are 4 m apart. The particle is held at point C, which is 2.5 m from point A, creating a straight line configuration of points A, B, and C. When the particle is released from rest, the springs exert tension in different directions due to the displacement from their natural lengths. The discussion seeks clarification on how to diagram this setup and the forces acting on the particle. Understanding the tensions in the springs is crucial for solving the problem effectively.
aurao2003
Messages
122
Reaction score
0

Homework Statement



Hi
I can't seem to get a diagram for this question. Can anyone help and also please explain the subsequent diagram. This is the question. A particle of mass 0.8kg is attached to the ends of 2 identical light elastic springs of natural length 1.6m and modulus of elasticity 16N. The free ends of the springs are attached to 2 points where points A and B which are 4m apart on a smooth horizontal surface. The point C lies between A and B such that ABC is a straight line and AC = 2.5m. The particle is held at C and then released from rest.

My textbook has tensions acting in different directions. Can anyone explain? Thanks

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Consider two parallel walls at a distance of 4m apart. put a mass of 0.8kg 2.5m from one of the walls. now attach springs b/w the mass and each of the walls.

got it?
 
Thanks. I like the analogy. I will get back to you.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top