What Is the Direction of the Ball's Projection?

  • Thread starter Thread starter grando69
  • Start date Start date
  • Tags Tags
    Ball Direction
AI Thread Summary
To determine the direction of the ball's projection, the problem involves breaking down the initial speed of 20 m/s into horizontal and vertical components. The horizontal motion remains constant due to the absence of air resistance, while the vertical motion is influenced by gravity. The equations of motion are applied to find the relationship between the components and the time of flight, which is 1.5 seconds. By calculating the horizontal and vertical distances traveled, the angle of projection can be determined. Ultimately, the analysis reveals the necessary components to solve for the angle at which the ball was thrown.
grando69
Messages
1
Reaction score
0

Homework Statement


A child throws a ball with a speed 20ms-1 from a window 5m above horizontal ground. If the ball hits the ground 1.5 seconds later, find the direction of the projection.


Homework Equations


The basic equations of motion:
s=ut+1/2at^2
v=u+at
v^2=u^2+2as


The Attempt at a Solution

 
Physics news on Phys.org
What have you tried? Show your thoughts.
 
try breaking the speed of the ball into component form, so that you have a horizontal and a vertical component. assuming that there is no air resistance, the horizontal component will remain constant as there is no acceleration occurring in the horizontal plane. The only acceleration present is gravity which acts downwards in the vertical plane.
the horizontal component will be: ut\cos \theta
the vertical component will be: ut\sin \theta - \frac{{gt^2 }}{2}
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top