What is the distance and speed of a car with constant acceleration?

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AI Thread Summary
A car traveling at 50.0 m/s brakes to a stop in 6.00 seconds, prompting a discussion on calculating distance and speed during constant acceleration. To find the distance traveled before stopping, the equation v_f^2 = v_0^2 + 2ad is recommended. For determining the car's speed 1.35 seconds after braking begins, the formula v = a*t + v_0 is suggested, with emphasis on correctly applying signs for acceleration. Participants express confusion initially but receive guidance to solve both parts of the problem. The discussion highlights the importance of understanding kinematic equations in solving motion problems.
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Homework Statement


A car is moving at 50.0 m/s and brakes to a halt in 6.00 seconds.
(1)From the time it starts braking, how far does the car travel before the car comes to a halt if its acceleration is constant?
(2)What is the car's speed 1.35 s after it starts to brake if the cars acceleration is constant?


Homework Equations


v=a*t+vo


The Attempt at a Solution


I really just don't where to start with this problem. I'm confused! Please help!
 
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The equation you listed will get you the acceleration, but for the distance you'll need

v_f^2 = v_0^2 + 2ad
 
Ok thank you! I was able to find the distance for question one but I am still stuck as to what is the car's speed 1.35 s after it starts to brake if the cars acceleration is constant?
 
ScienceGirl90 said:
Ok thank you! I was able to find the distance for question one but I am still stuck as to what is the car's speed 1.35 s after it starts to brake if the cars acceleration is constant?

Just use the first formula you gave in your original post. Pay attention to your signs and you'll be golden.
 
Got it. Thanks!
 

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