What is the Electric Field at the Origin Due to Two Point Charges?

AI Thread Summary
The discussion focuses on calculating the electric field at the origin due to two point charges: a +8 µC charge at (3,5) m and a -2 µC charge at (3,-2) m. The formula used is E = kq/r^2, where k is 9x10^9. Participants discuss the correct approach to find the x and y components of the electric field, emphasizing the need to account for the direction of the electric field vectors based on the sign of the charges. A common mistake identified is miscalculating the direction of the electric field from the negative charge and the importance of correctly applying trigonometric functions to resolve components. Ultimately, the correct values and signs for the electric fields are crucial for obtaining the accurate resultant electric field at the origin.
negatifzeo
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Homework Statement


A +8·µC charge is located at coordinates (3,5)·m, and a -2·µC charge is located at coordinates (3,-2)·m. Find the electric field at the origin.
E= ? V/m x + ? V/m y

(It asks for the solution in x and y components)

Homework Equations


I was using E=kq/r^2, where E is the electric field vector (Away if positive, towards if negative) K was 9x10^9, q is the value of the charge.


The Attempt at a Solution


First I used pythagorean theorem to determine distance to origin. Then I used this value for r.
Using the formula for the +8 charge I get E=2117.61 and for the -2 charge I got E=1376.63. Then I used the trig functions from the triangles to solve for the components, which I thern added together for the wrong answer. Where have I gone wrong here?
 
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-2 charge, E=1376.63, it should be negative, or pointing into the right so when you add the 2 E vectors you will be subtracting them.

I get the same values for E's, just that negative sign, Hope that's the problem!
 
The angles from the original triangles are used to calculate the components, correct? I was treating the +8 charge as my negative vector as electric fields point outwards from positive charges, right?
 
Yes,

I think if you use the 8 charge as the negative, you will get the wrong answer, maybe just -1*answer wil fix it but I'm not 100% sure on that.

You should find the 2 vector pointing away, then inverse it so it points inward and then find the x-y components and subtract or add the components.

Also for your -2 charge, I got E=1384.62 not 1376.63
 
Hi negatifzeo,

negatifzeo said:

Homework Statement


A +8·µC charge is located at coordinates (3,5)·m, and a -2·µC charge is located at coordinates (3,-2)·m. Find the electric field at the origin.
E= ? V/m x + ? V/m y

(It asks for the solution in x and y components)

Homework Equations


I was using E=kq/r^2, where E is the electric field vector (Away if positive, towards if negative) K was 9x10^9, q is the value of the charge.


The Attempt at a Solution


First I used pythagorean theorem to determine distance to origin. Then I used this value for r.
Using the formula for the +8 charge I get E=2117.61 and for the -2 charge I got E=1376.63. Then I used the trig functions from the triangles to solve for the components, which I thern added together for the wrong answer. Where have I gone wrong here?

What components and wrong answer did you get?
 
I finally got the correct answer, my problem was rounding a bit too much.
 
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