SUMMARY
The electrical potential energy stored in the membrane of a nerve cell can be calculated using the capacitance and the potential difference. Given the axon membrane's capacitance of 1.0 µF/cm², a length of 12 mm, and a diameter of 150 µm, the surface area is approximately 0.00377 m². The resting potential difference of -90 mV results in an electrical potential energy of approximately 0.0001695 joules. The charge on each surface can be determined using the formula Q = C × V, yielding a charge of approximately 1.515 × 10^-5 coulombs, equivalent to 9.47 × 10^13 electron charges.
PREREQUISITES
- Understanding of capacitor formulas and calculations
- Familiarity with the concept of electrical potential energy
- Knowledge of basic geometry for calculating surface area
- Concept of resting potential in nerve cells
NEXT STEPS
- Study the relationship between capacitance and potential difference in capacitors
- Learn about the biophysics of nerve cell membranes and their electrical properties
- Explore the mathematical derivation of the surface area of cylindrical objects
- Investigate the role of ion channels in establishing resting potential
USEFUL FOR
Students studying biology or biophysics, educators teaching about nerve cell physiology, and anyone interested in the electrical properties of biological membranes.