What is the equation for finding the displacement of a falling object?

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Homework Help Overview

The problem involves a bullet shot vertically upward with an initial velocity of 655 m/s, and the goal is to determine how far above the muzzle the bullet will be after 1.0 second. The subject area is kinematics, specifically dealing with motion under the influence of gravity.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various kinematic equations that relate velocity, acceleration, and displacement. There is an emphasis on identifying which equations are applicable given the initial conditions of the problem.

Discussion Status

Several participants have reiterated the relevant kinematic equations and have pointed out the known variables, such as initial velocity, time, and gravitational acceleration. There is a suggestion to solve for final velocity to aid in determining the distance, indicating a productive direction in the discussion.

Contextual Notes

Participants are working within the constraints of the problem as stated, focusing on the provided initial conditions and the effects of gravitational acceleration without resolving the final displacement.

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Homework Statement



The problem is: A bullet shot vertically upward leaves the gun at a velocity of 655 m/s. How far above the muzzle will the bullet be 1.0 s after it is fired?

Homework Equations





The Attempt at a Solution



I know that i have the time (1 s) and the velocity (655 m/s). I just don't know how to find the other parts and then which equation to use to find how far above the muzzle the bullet will be.
 
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Clearly the bullet has an initial velocity and will be subject to gravitational acceleration. What kinematic formulas do you know that involve velocity and acceleration?
 
gneill said:
Clearly the bullet has an initial velocity and will be subject to gravitational acceleration. What kinematic formulas do you know that involve velocity and acceleration?

v = x/t
avg.v = v + initial v/2
v = initial v + at
x - initial x = initial vt + 1/2at^2
v^2 = initial v^2 + 2a(x-initial x)
 
Nevermind, gneill's suggestion is better.

lindseyam said:
v = x/t
avg.v = v + initial v/2
v = initial v + at
x - initial x = initial vt + 1/2at^2
v^2 = initial v^2 + 2a(x-initial x)

You know initial velocity, time, and acceleration (gravity, as gneill pointed out). You can solve for final velocity, which will allow you to then solve for distance.

Does that make sense?
 
Last edited:
lindseyam said:
v = x/t
avg.v = v + initial v/2
v = initial v + at
x - initial x = initial vt + 1/2at^2
v^2 = initial v^2 + 2a(x-initial x)

Your fourth equation looks promising...
 

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