What is the equation for simple harmonic motion with A=14cm and ω=3.0Hz?

[negation]

Homework Statement

Write a simple harmonic motion with amplitude 14cm , frequency 3.0Hz , and maximum displacement at t=0.

The Attempt at a Solution

y (t) = A cos (ωt) = 14 cos (2πt/T)
Dealing with angular frequency is easy. But deal with natural frequency throws me off course.

 

[collinsmark]

Physics doesn't require much memorization compared to other fields of study. But here are a couple of relationships that are exceptions, and you might want to commit them to memory:

f = \frac{1}{T}
\omega = 2 \pi f

Where T is the period, ω is the angular frequency (i.e., radial frequency), and f is the simple frequency (i.e., ordinary frequency). (Some textbooks represent the simple frequency with the Greek letter nu, \nu, which looks too much like a 'v' to me, but it's often used anyway. Just be aware of that.)

 

[negation]

Physics doesn't require much memorization compared to other fields of study. But here are a couple of relationships that are exceptions, and you might want to commit them to memory:

f = \frac{1}{T}
\omega = 2 \pi f

Where T is the period, ω is the angular frequency (i.e., radial frequency), and f is the simple frequency (i.e., ordinary frequency). (Some textbooks represent the simple frequency with the Greek letter nu, \nu, which looks too much like a 'v' to me, but it's often used anyway. Just be aware of that.)

Thanks. Frequency is the number cycles per second. In order to have it converted to radians, and by definition of one cycle = 2 pi, the product of f and 2pi gives radians s^-1