What is the equivalent capacitance for this circuit?

AI Thread Summary
The discussion focuses on finding the equivalent capacitance of a circuit, with participants sharing their approaches. Key equations for capacitance in series and parallel configurations are provided. One user suggests simplifying the circuit by first solving components in series without junctions. Another participant confirms that their calculations yield an equivalent capacitance of 3μF, agreeing that this result is likely correct. The conversation emphasizes the importance of correctly identifying series and parallel components to simplify the problem.
KeithLucas
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Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1


The Attempt at a Solution


See the first penciled attachment.
 

Attachments

  • CCF11142012_0000.jpg
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  • CCF11142012_0002.jpg
    CCF11142012_0002.jpg
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KeithLucas said:

Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1


The Attempt at a Solution


See the first penciled attachment.

I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.
 
superdave said:
I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.

Which ones are in series with no junctions in between? I've posted the original circuit in one attachment, but another attachment has my attempt where I thought I solved everything in series.
 
KeithLucas said:
Which ones are in series with no junctions in between?
Top and top left.
 
KeithLucas said:

Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1

The Attempt at a Solution


See the first penciled attachment.

your penciled attempt work out to be 3μF, which is same as mine and i think it is correct.
 
Last edited:
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