What is the excess charge on the surface of the earth?

AI Thread Summary
The discussion centers on calculating the excess charge on the Earth's surface based on its vertical electric field of 117 N/C. The initial attempt to use the equation E = ke*Q/r^2 was unsuccessful, prompting suggestions to apply the formula for electric flux instead. The correct approach involves using the net electric flux, which is the product of the electric field and the surface area of the Earth, equating it to the excess charge divided by the permittivity constant. The permittivity constant is noted as 8.85 x 10^-12. This exchange highlights the importance of using the appropriate formulas in electrostatics calculations.
gallib
Messages
4
Reaction score
0

Homework Statement



The Earth has a vertical electric field at the surface, pointing down, that averages 117 N/C. This field is maintained by various atmospheric processes, including lightning. What is the excess charge on the surface of the earth?


Homework Equations



E=ke*Q/r^2 Q=Er^2/ke

The Attempt at a Solution



I attempted to plug in E = 117, r= radius of the earch, and ke= 8.99*10^9 into the equation to find Q, but this answer was wrong. Any ideas, thanks.
 
Physics news on Phys.org
Why don't you use the formula for Electric flux? The Net electric flux through surface is basically Electric field * (4pi*(radius of Earth ^ 2)) = excess charge / permittivity constant.
 
Ah..thank you.
 
Last edited:
Yeah, permittivity constant is 8.85*10^-12.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top