What is the Expected Number of Defective Keyboards?

AI Thread Summary
The discussion focuses on calculating the expected number of defective keyboards from a batch where 10% are defective. The relevant probability distribution is identified as the binomial probability distribution, with parameters n=3 (the number of keyboards) and p=0.10 (the probability of a keyboard being defective). It is clarified that the expected value cannot be found by simply multiplying the probability distribution by 3; instead, it requires calculating the sum of the products of the number of defective keyboards and their respective probabilities. Alternatively, the expected value can be directly computed using the formula NP, where N is the number of trials and P is the probability of a defect. This approach leads to a clearer understanding of the expected number of defective keyboards.
kevykevy
Messages
25
Reaction score
0

Homework Statement



10% of the keyboards a computer company manufactures are defective. 3 keyboards come off the assembly line. Determine the probability distribution, where x=the number of defective keyboards. What would the expected number of defected keyboards be?


Homework Equations



I haven't done data management in over a year, this is the reason I can't do the question...I don't know what the equation is for probability distribution.


The Attempt at a Solution



After finding the probability distribution, I suppose I can just multiply it by 3?
 
Physics news on Phys.org
There is no one probability distribution. What you want is the "binomial probability distribution". If, on each trial, an event happens with probability p, then the probability the event will happen i times in n trials is P(i)= _nC_i p^i(1-p)^{n-i} where _nC_i is the "binomial coefficient". Here, n= 3 and p= 0.10.

No, you cannot just multiply the probability distribution by 3. The expected value in 3 "trials" is 0P(0)+ 1P(1)+ 2P(2)+ 3P(3). That is, for i= 0, 1, 2, 3, you multiply the probability that many are faulty by the number, then add.
 
Alternatively, you can just use the fact that for a binomial distribution with number N and probability P, the expected value is NP.
 
Back
Top