What is the explanation for the inequality in Rudin 1.21?

[Unassuming]

In Rudin 1.21 he says the following in the midst of proving a theorem,

"The identity b^{n} - a^{n}= (b-a)(b^{n-1} + b^{n-2}a + ... + a^{n-1}) yields the inequality

b^{n} - a^{n} < (b-a)nb^{n-1} when 0 < a < b"

I can understand that it is less than, but I cannot understand how it is coming (yielding) from the identity.

Any explanation would be greatly appreciated.

 

[Vid]

Try seeing what happens to the second term on the right side when b=a.

 

[sutupidmath]

Vid's point is that:

b^n-a^n=(b-a)(b^{n-1}+b^{n-2}a+...+ba^{n-2}+a^{n-1})&lt;(b-a)\underbrace{(b^{n-1}+b^{n-2}b+...+bb^{n-2}+b^{n-1})}=(b-a)nb^{n-1} since a<b

 

[Unassuming]

...that's clever. Thank you.