What is the final position of the object?

  • Thread starter Thread starter Angela_vaal
  • Start date Start date
  • Tags Tags
    Final Position
AI Thread Summary
The discussion revolves around calculating the final position of an object given its initial position of 0.40 m and a work done of -0.19 J. Participants explore the implications of moving the object to the left, as positive work would not achieve the required negative work. Through calculations, they determine that moving from 0.40 m to 0.25 m results in 0.12 J of work, and moving from 0.25 m to 0.13 m adds another 0.072 J, totaling 0.192 J. The final position is concluded to be 0.13 m, confirming the calculations align with the negative work requirement. The collaborative effort highlights the importance of understanding force direction and work in physics.
Angela_vaal
Messages
59
Reaction score
1

Homework Statement


What is the final position of the object if its initial position is x = 0.40 m and the work done on it is equal to -0.19 J?
Walker4e.ch07.Pr036.jpg


Homework Equations



work(J)= Fx ΔX

The Attempt at a Solution


I do not know where to begin? please give me a hint where to begin.
 
Physics news on Phys.org
It starts at 0.4m. What strength of force acts on it there, and in which direction?
If it were then moved by the force to 0.5m, how much work has the force done?
 
haruspex said:
It starts at 0.4m. What strength of force acts on it there, and in which direction?
If it were then moved by the force to 0.5m, how much work has the force done?
work would be .08 J in positive direction
 
Angela_vaal said:
work would be .08 J in positive direction
Right. Is that going in the right direction to reach a work done of -0.19 J?
 
haruspex said:
Right. Is that going in the right direction to reach a work done of -0.19 J?

No it would not. You would have to go to the left side.
 
Angela_vaal said:
No it would not. You would have to go to the left side.
Right, so go to the left, but stop when you get to a change in the force and see how the total work is going.
 
haruspex said:
Right, so go to the left, but stop when you get to a change in the force and see how the total work is going.

I believe it is either between .12m or .11 m? Am i right?
 
Angela_vaal said:
I believe it is either between .12m or .11 m? Am i right?
Do you mean between x=.11m and x=.12m, or between .11m and .12m left of the 0.25m mark?
Either way, please post your working.
 
haruspex said:
Do you mean between x=.11m and x=.12m, or between .11m and .12m left of the 0.25m mark?
Either way, please post your working.

from x=.40m to x=.25m work is= .12J
from x=.25m to x=.13m work is = .072 j

total work =.192 J. since I am working backwards I am assuming the answer is negative.

Therefore, my final position would be .13 m?
 
  • #10
Angela_vaal said:
from x=.40m to x=.25m work is= .12J
from x=.25m to x=.13m work is = .072 j

total work =.192 J. since I am working backwards I am assuming the answer is negative.

Therefore, my final position would be .13 m?
Yes.
 
  • #11
haruspex said:
Yes.

Thank you for the help! :)
 

Similar threads

Finding the final y-position of a projectile
Replies
8
Views
3K
Which directions should be set to positive? Impulse/momentum
Replies
3
Views
2K
Solving for final position with a negative work value
Replies
2
Views
2K
Calculating Work Done by a Variable Force
Replies
2
Views
3K
Determining position of an object after inelastic collision
Replies
1
Views
2K
Questions Regarding a Cat Going Up a Ramp
2
Replies
56
Views
4K
Final velocity of a mass moving through friction
Replies
4
Views
2K
Positive or negative final velocity? Constant acceleration
Replies
8
Views
4K
Is potential energy defined only for internal conservative forces?
Replies
15
Views
1K
Forces on an object in vertical circular motion
Replies
8
Views
2K

Hot Threads

Recent Insights

Back
Top