What Is the Final Velocity of a Particle Under a Time-Dependent Force?

AI Thread Summary
A particle initially at rest experiences a time-dependent force, F(t) = F0*e^(-at), which influences its velocity over time. As time approaches infinity, the particle's velocity converges to a specific value determined by the constants F0 and a. The impulse can be calculated by integrating the force over time, but challenges arise in solving the integral. The final velocity equation derived suggests that as time increases, the velocity approaches a constant value, which can be found using initial conditions. Ultimately, the discussion centers on understanding the relationship between force, impulse, and velocity in the context of a time-dependent force.
Alex Wik
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Homework Statement


A particle with the mass m moves in one dimension. It is in rest when t=0 and affects later after a by The time dependent force. F(t) =F0*e^(-at) where F0 and a is constants. When The time is really big The particels velocity get close to a spesific value. What is it?

Homework Equations


F(t) =F0*e^(-at)
I= delta(p)

The Attempt at a Solution


[/B]
I have tried to take The intergrals of both sides. F(t) =F0*e^(-at)--> I (impulse) = integrals from 0 to infinite( F0*e^(-at) /-at) But later on I can not seem to be a solve this general intergrals. And then i need to solve The velocity from the impulse.
 
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Sorry, I posted a wrong answer just a moment ago...

Do you know what is the integral of ∫ e^x dx ?
 
Phylosopher said:
Sorry, I posted a wrong answer just a moment ago...

Do you know what is the integral of ∫ e^x dx ?
Yes. It is e^x+C
 
Alex Wik said:
Yes. It is e^x+C

Very good. Now, what can you do for e^-at so that it looks more like e^x ?
 
Please do not post in boldface type.

Alex Wik said:

Homework Statement


A particle with the mass m moves in one dimension. It is in rest when t=0 and affects later after a by The time dependent force. F(t) =F0*e^(-at) where F0 and a is constants. When The time is really big The particels velocity get close to a spesific value. What is it? [/B]

Do you mean for both the ##a## values I put in red to be the same?

Homework Equations


F(t) =F0*e^(-at)
I= delta(p)
[/B]

The Attempt at a Solution


What is ##p##? What impulse?

I have tried to take The intergrals of both sides. F(t) =F0*e^(-at)--> I (impulse) = integrals from 0 to infinite( F0*e^(-at) /-at) But later on I can not seem to be a solve this general intergrals. And then i need to solve The velocity from the impulse.
 
LCKurtz said:
Please do not post in boldface type.
Now fixed in the OP.

Alex Wik said:
have tried to take The intergrals of both sides. F(t) =F0*e^(-at)--> I (impulse) = integrals from 0 to infinite( F0*e^(-at) /-at) But later on I can not seem to be a solve this general intergrals.
"Intergrals" is not a word -- the correct spelling is integrals.
 
Alex Wik said:
I have tried to take The intergrals of both sides. F(t) =F0*e^(-at)--> I (impulse) = integrals from 0 to infinite( F0*e^(-at) /-at) But later on I can not seem to be a solve this general intergrals. And then i need to solve The velocity from the impulse.
If I understand what you wrote, you said
$$\text{Impulse} = \int_0^\infty F(t)\,dt = \int_0^{\infty} \frac{F_0 e^{-at}}{-at}\,dt.$$ Is that what you meant?
 
Alex Wik said:
particle with the mass m moves in one dimension. It is in rest when t=0 and affects later after a by The time dependent force. F(t) =F0*e^(-at) where F0 and a is constants. When The time is really big The particels velocity get close to a spesific value. What is it?
v(t)=-F0/(ma)exp(-at)+c
for large t clearly v=c.
c can be determined from the boundary condition at t=0 which is F0/ma
 
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