# What is the force exerted by one crate on the other?

1. Feb 23, 2010

### huybinhs

1. The problem statement, all variables and given/known data

Two crates rests on the floor, one next to the other. A man pushes with a horizontal force of 400 N on the larger (50.0 kg) crate, which, in turn, pushes the other (25.0 kg) so that both slide as he walks along. Each crate experiences a friction force opposing the motion equal to 40% of its weight.

1.Determine the acceleration of the crates.

2.What is the force exerted by one crate on the other?

2. Relevant equations and 3. The attempt at a solution

1) total friction force Ff = 40 x (50+25) x 9.8/100 = 294 N
=>F(net) = F(applied) - Ff
=>F(net) = 400 - 294 = 106 N
=>By F = ma
=>106 = 75 x a
=>a = 106/75 = 1.41 m/s^2 => CORRECT

2. Feb 24, 2010

### dineshnaveen

the answer is 200N. i did i have take one crate and i calculated the force.according to the force exerted by one is exactly opposite to athor

3. Feb 24, 2010

### dineshnaveen

the answer is 200N. i did i have take one crate and i calculated the force.according to the force exerted by one is exactly opposite to anthor

4. Feb 24, 2010

### dineshnaveen

the answer is 200N. i did i have take one crate and i calculated the force.according to the force exerted by one is exactly opposite to anothor

5. Feb 24, 2010

### mparsons06

The force exerted on one crate to the other is:

A = 50 kg; B = 25 kg

F = ma
400 = 75.0 kg x a
a = 5.3 m/s^2

F + F(BA) = m1 x a
F + F(BA) = 50 kg x 5.3 m/s^2
F + F(BA) = 265 N

F + F(BA) = 265 - F
F(BA) = 265 - 400
F + F(BA) = -135 N (But put in 135 because that's the correct answer)

6. Feb 24, 2010

### huybinhs

Thanks! I got it!