What is the formula for the charge of a charged soap bubble?

Pandabasher
Messages
10
Reaction score
0

Homework Statement


A soap bubble of radius 0.1mm has a wall thickness of 3.3x10^-8m, and is charged to a potential of 100V. Give a formula for the charge of the bubble.

I know this is probably a really easy question, but I've only ever done problems with spheres of negligible wall thickness, so not sure if the wall makes a difference.
I know the equation for potential, so I could just rearrange that to get get Q.

Any help is appreciated, cheers.
 
Physics news on Phys.org
Some malicious profs have a tendency to give you irrelevant data. Did you know that? :biggrin:

Real question is: what is the outside radius? Is it 0.1mm or 0.1mm + 3.3e-8m? The problem as stated doesn't say, but you'll have to make an assumption. Of course, 3.3e-8 << 1e-4.
 
I think the point is that the thickness IS negligible as you say, so I've been trolled by Professor after all, haha. Thanks.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top