- #1
badman
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A satellite of mass 1900 kg used in a cellular telephone network is in a circular orbit at a height of 690 km above the surface of the earth.
What is the gravitational force on the satellite?
Take the gravitational constant to be G = 6.67×10−11 N*m^2/kg^2, the mass of the Earth to be m_e = 5.97×1024 kg, and the radius of the Earth to be r_e = 6.38×106 m.
my answer was 1.51*10^4 {\rm N} which was correct, but I am confused on the next question: What fraction is this of its weight at the surface of the earth?
Take the free fall acceleration to be g = 9.80 m/s^2.
What is the gravitational force on the satellite?
Take the gravitational constant to be G = 6.67×10−11 N*m^2/kg^2, the mass of the Earth to be m_e = 5.97×1024 kg, and the radius of the Earth to be r_e = 6.38×106 m.
my answer was 1.51*10^4 {\rm N} which was correct, but I am confused on the next question: What fraction is this of its weight at the surface of the earth?
Take the free fall acceleration to be g = 9.80 m/s^2.