What is the Implicit Differentiation Equation for eysinx=x+xy?

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Equation: eysinx=x+xy

I took the derivative of both sides.
For the side with eysinx, I used the product rule and chain rule to get: ey*cosx + ey*sinx*y'
For the side with x+xy, I used the sum and product rule to get 1+y+xy'

So my resulting equation is: ey*cosx + ey*sinx*y'=1+y+xy', which I don't know how to solve and is probably wrong.
 
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Why would you not knowhow to solve that for y'? If the problem were A+ By'= C+ Dy', could you solve for y'?
 
express y' as a function of x and y
 

Thread 'Finding the nth roots of a complex number'

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