- #1
MillerL7
- 14
- 0
Evaluate the indefinite integral:
[(e^(4x))/(e^(8x))+9]dx
-I think that u=e^(2x)
so then du=e^(2x)dx
then the answer would end up being [(e^(4x)+9)/(-1)]^(-1)
but it was incorrect; I think that my u might be wrong and that's where the problem is, but I am not sure. Please help, thank you!
[(e^(4x))/(e^(8x))+9]dx
-I think that u=e^(2x)
so then du=e^(2x)dx
then the answer would end up being [(e^(4x)+9)/(-1)]^(-1)
but it was incorrect; I think that my u might be wrong and that's where the problem is, but I am not sure. Please help, thank you!