What is the input voltage for the second stage in a 2-stage amplifier?

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    Amp Gain Output
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The discussion focuses on calculating the gain of a two-stage amplifier, emphasizing the importance of loading effects between stages. The gain formula is presented as A = A1 x A2 x (rin2 / (rin2 + ro1)), where 'p' represents the loading factor. The contributor seeks clarification on how to derive this loading factor mathematically, linking it to the voltage divider concept. It is noted that the input voltage for the second stage is affected by this voltage divider, leading to the equation Vin2 = Vin x A1 x Rin/(Rout + Rin). Understanding these relationships is crucial for accurate gain calculations in amplifier design.
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Hello all. I am currently trying to find the gain of a 2 stage amp. According to some notes I have, it is:

A = A1 x A2 x (rin2 / (rin2 + ro1))
Where
A1 = gain of first stage
A2 = gain of second stage
rin2 = input resistance of second stage
ro1 = output resistance of first stage

Let p = (rin2 / (rin2 + ro1)) so that A = A1 x A2 x p

I understand conceptually why 'p' comes in. It is due to loading of the stages together (right?).
But I don't understand how to get that factor ('p') mathematically. Please explain. Thank you.

PS: If a schematic of the amplifier is needed please let me know.
 
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In electronic circuits, we always hooking the output of something (output of a amplifier, output of a voltage input source...) to the input of something else (load resistor, input stage of a next amplifier...).
After we draw this in a simplified schematics we see our old friend the voltage divider.

95_1246404388_thumb.png


p = Voltage divider equation

So the second stage input voltage is not equal to

Vin2 = Vin x A1 because we have a voltage divider in the circuit, so the second stage input voltage is equal to.

Vin2 = Vin x A1 x Rin/(Rout + Rin)
 
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