What is the Integral of 1 / 1 + sqrt [x] Using the Chain Rule and Substitution?

[Charas]

Hi, I am a newbie here and would like to ask you stg. integral of 1 / 1 + sqrt [x]

I used chain rule and used x = u^2 is that true?

Thanx for any replies

 

[leright]

Do the substitutions that neutrino and morphism suggested.

 

[kingdomof]

Can't you use integration by parts?

 

[evilpostingmong]

I'm doing this in my head and not fully awake, so I could be wrong.
we have 1/(1+sqrt(x)) You can use the substitution that you've shown.
u^2=x
2udu=dx
So we end up with 2u/1+u
remember you can substitute more than once...