What Is the Interval of Convergence for the Given Series?

Ki-nana18
Messages
90
Reaction score
0

Homework Statement


The summation from n=1 to infinity of ((n!)x^(2n))/((2n-1)!) Find the Interval of Convergence of this series.


Homework Equations


Ratio test


The Attempt at a Solution


I applied the ratio test, then got x^2 times the limit as n approaches infinity of (n+1)/(2n(2n+1)). I took the limit and got zero and since 0<1 the series converges. Does this mean the interval of convergence is (-infinity,+infinity)?
 
Physics news on Phys.org
Yes, the limit of the ratio is zero. So that's exactly what it means. The interval of convergence is (-infinity,infinity).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
1
Views
1K
Replies
5
Views
2K
Replies
2
Views
1K
Replies
3
Views
2K
Replies
11
Views
3K
Replies
4
Views
1K
Replies
3
Views
1K
Back
Top