What is the Magnetic Field Strength of a Magnetron at a Resonant Frequency?

AI Thread Summary
The discussion focuses on calculating the magnetic field strength of a magnetron at its resonant frequency of 2.82×10^10 s-1, with an electron period of revolution of 3.55×10^-11 s. The participant expresses uncertainty about how to relate centripetal force to magnetic force and how to derive velocity and radius from the given period. A suggestion is made to consider the speed of an electron moving in a circular path, which can be derived from the period. The conversation highlights the need for additional equations to solve the problem effectively. Understanding these relationships is crucial for determining the magnetic field strength.
Hellphish
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Homework Statement



A magnetron is a microwave source in which a "bunch" of electrons travel on a circular orbit in a uniform magnetic field. As the electrons pass the electrodes, a high-frequency alternating voltage difference occurs. Suppose the resonant frequency is f = 2.82×10^10 s-1; that is, the electron period of revolution is T = 3.55×10^-11 s. What is the corresponding strength of the magnetic field?
The electron charge is -1.6E-19 C and the electron mass is 9.1E-31 kg.

Homework Equations



f=qv * b
where q is the charge, v is the velocity, and b is the magnetic field

The Attempt at a Solution



I think I need to set a centripetal force equal to the magnetic force. The only equation I know for centripetal force is f=m(v^2 / r) and I'm not sure how to solve that with the period. I'm really just not sure if I'm even going about this right or how I can solve for v and r. Any help would be appreciated.
 
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Hellphish said:

Homework Statement



A magnetron is a microwave source in which a "bunch" of electrons travel on a circular orbit in a uniform magnetic field. As the electrons pass the electrodes, a high-frequency alternating voltage difference occurs. Suppose the resonant frequency is f = 2.82×10^10 s-1; that is, the electron period of revolution is T = 3.55×10^-11 s. What is the corresponding strength of the magnetic field?
The electron charge is -1.6E-19 C and the electron mass is 9.1E-31 kg.

Homework Equations



f=qv * b
where q is the charge, v is the velocity, and b is the magnetic field

The Attempt at a Solution



I think I need to set a centripetal force equal to the magnetic force. The only equation I know for centripetal force is f=m(v^2 / r) and I'm not sure how to solve that with the period. I'm really just not sure if I'm even going about this right or how I can solve for v and r. Any help would be appreciated.

You are only missing one equation (which is quite simple). Consider a particel going in a circle of radius r. If it takes a time T to go around once, what is the speed of the particle?
 
Oh wow, I didn't even think of that. Thanks.
 
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