What is the Magnitude of Average Force Due to Air Resistance?

AI Thread Summary
The discussion revolves around calculating the average force due to air resistance on a projectile. The initial problem involves a projectile with a mass of 1.100 kg shot upwards at 29.0 m/s, with part A already solved for maximum height without air friction. For part B, participants suggest using Newton's second law and kinematic equations to find the average force of air resistance, given that the projectile only reaches a height of 35.2 m. The equations discussed include solving for acceleration and time through a system of equations. The conversation highlights the importance of understanding these principles to determine the impact of air resistance on projectile motion.
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Hello ! Wow, you guys are awesome, Thanks for all the help ! I've got another one I'm stuck on - ... I got part A.. the answer is 42.9082, but I can't get part B... ? help pleaaseee? thaaanks

A projectile of mass 1.100 kg is shot straight up with an initial speed of 29.0 m/s.
(a) How high would it go if there were no air friction?
m
(b) If the projectile rises to a maximum height of only 35.2 m, determine the magnitude of the average force due to air resistance.
N
 
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Use the second law of Newton: You would have -mg - Fr = ma

similarly, by the kinematic equations, you can find aceleration by using a system of equations: v = v0 + at and x = x0 + v0t + (1/2)at^2

in the first, v is o since at the top the velocity is o, you really have two equations with two uknownsl; t and a.

once you have "a" you can use -mg - Fr = ma or Fr = mg-ma

Hope i was some help here. (tell me if i did something wrong, i make mistakes sometimes)
 
hm.. i didn't really understand what u said at all.. how am i supposed to find a when i don't know t ? ah, confused
 
its a system of equations that gets you t and a. The systems are
-29 = at
35.2 = 29t + (1/2)at^2
these two help you solve for a AND t (not that you need t)
does that help?
 
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