What is the magnitude of the acceleration of an electron

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The magnitude of the acceleration of an electron in a uniform electric field of 4.20 x 10^6 N/C is calculated to be 0.73 x 10^18 m/s². It takes approximately 0.40 x 10^-10 seconds for the electron to reach one-tenth the speed of light from rest. However, there is confusion regarding the distance traveled in that time, as the initial calculation using the formula d = at²/2 yielded an incorrect result. The computed distance was 0.000584 meters, but this was deemed incorrect by the user. Clarification on the computation method is needed to resolve the discrepancy.
athos
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Please help on the last question. Most likely it's something simple, but I just can't see it. Thanks.
(a) What is the magnitude of the acceleration of an electron in a uniform electric field of 4.20 106 N/C?
a= 0.73x10^18 m/s2 (Correct)

(b) How long would it take for the electron, starting from rest, to attain one-tenth the speed of light?
t= 0.40x10^-10 s (Correct)

(c) How far would it travel in that time?
I applied d=at^2/2, with the above values for a and t, but it is not correct.

Thanks.
 
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Maybe you are just doing the computation wrong. Everthing seems right, you should get the right answer...
 
d=at^2/2=0.73x10^18x0.4x10^-10x0.4x10^-10/2=0.0584x10^-2= 0.000584 (m), but it comes back as incorrect. Thanks for quick reply.
 
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