What is the magnitude of the force of the block on the horizontal surface?

AI Thread Summary
The block has a weight of 2.9 N and is subject to an upward force of 1.3 N from a string. To find the force exerted by the block on the horizontal surface, the upward force must be subtracted from the weight. The correct calculation shows that the block pushes down on the surface with a force of 2.9 N - 1.3 N, resulting in a net force of 1.6 N. This reflects the balance of forces acting on the block while it remains at rest. Understanding these force interactions is crucial for solving similar physics problems.
Nance
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Homework Statement



A block with a weight of 2.9 N is at rest on a horizontal surface. A 1.3 N upward force is applied to the block by means of attached vertical string.
(a) What is the magnitude of the force of the block on the horizontal surface?

Homework Equations



I'm not sure really..

The Attempt at a Solution



I have tried solving this from several different angles. I thought to use F=2.9Nx9.81-1.3, but I believe that is incorrect.
 
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Nance said:
I have tried solving this from several different angles. I thought to use F=2.9Nx9.81-1.3, but I believe that is incorrect.

This looks right except I don't think you want to multiply the 2.9N force with a 9.81, which I believe would be the acceleration of the block towards the Earth in ms^{-2}. Force cross acceleration is not something people are usually interested in, especially if they are in the same direction, because it equals zero.

Imagine the block pushing the surface with 2.9N force and an opposing force of 1.3N acts in the opposite direction to cancel out 1.3N of the original force acting on the surface. Hope this helped.
 
Thank you!
 

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