What is the Marginal PDF of X?

Phox
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Homework Statement



Let X and Y be random variables of the continuous type having the join p.d.f.:

f(x,y) = 8xy, 0<=x<=y<=1

Find the marginal pdf's of X. Write your answer in terms of x.

Find the marginal pdf's of X. Write your answer in terms of x.

Homework Equations





The Attempt at a Solution



f1(x) = integral(8xy)dy from 0 to 1

f2(y) = integral(8xy)dx from 0 to 1

f1(x) = 4x
f2(x) = 4y

This isn't right. what am I doing wrong?
 
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Ok, so i guess the bounds of f1(x) were supposed to be from x to 1.

And the bounds from f2(y) were supposed to be from 0 to y.

But I don't don't understand why
 
Phox said:

Homework Statement



Let X and Y be random variables of the continuous type having the join p.d.f.:

f(x,y) = 8xy, 0<=x<=y<=1

Find the marginal pdf's of X. Write your answer in terms of x.

Find the marginal pdf's of X. Write your answer in terms of x.

Homework Equations





The Attempt at a Solution



f1(x) = integral(8xy)dy from 0 to 1

f2(y) = integral(8xy)dx from 0 to 1

f1(x) = 4x
f2(x) = 4y

This isn't right. what am I doing wrong?

Before doing any calculations, draw the region f > 0 in the (x,y) plane; that is, draw the region
0 ≤ x ≤ y ≤ 1.
 
I've graphed it. I'm not sure what this tells me
 
Phox said:
I've graphed it. I'm not sure what this tells me

The marginal pdf ##f_X(x)## of X is the y-integral (with fixed x), integrated over the whole relevant y-region for that value of x. The drawing tells you what that region that would be.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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