What Is the Mass Flow Rate at Exit in a Steady Flow System?

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The discussion revolves around calculating the mass flow rate at the exit of a steady flow system where air is heated before exiting a piping junction. Given the volumetric flow rates and temperatures at the inlets and outlet, along with the pressure and specific heat capacity, participants are tasked with finding the mass flow rate, heat rate of the electric heater, and exit velocity of air. The equations provided include mass conservation and energy balance, but there are concerns about the signs in the calculations. Clarification is requested to ensure the equations are set up correctly. Accurate calculations are essential for understanding the system's performance.
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Homework Statement



Air flows steadily into a well isnulated piping junction through the two pipes and is heated by an electric resistor at uknown rate befoe exiting through the pipe. Pressure renaubs approcimetaly constant
p=0.1 MPa, first inlet: volumetric flow rate = 10m^3/s, t1= 20 C, 2nd inlet: volumetric flow rate = 30m^3/s, t2= 30C. At the outlet: t3= 55C, cross section area = 2m^2. Assume the effects of kinetic and potential energy are negligible and air behaves as a perfect gas iwth Cp= 1,0kJ/(kgK). Find the : mass flow rate at exit, heat rate of electric heater and exite velocity of air.

Homework Equations

The Attempt at a Solution

:
m1+m2=m3
Q-W= m1*ht1 + m2*ht2 - m3*ht3
W=0
Q=m1ht1+m2ht2-(m1+m2)ht3
m=A*ro*velocity
[/B]
 
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madzior771 said:

Homework Statement



Air flows steadily into a well isnulated piping junction through the two pipes and is heated by an electric resistor at uknown rate befoe exiting through the pipe. Pressure renaubs approcimetaly constant
p=0.1 MPa, first inlet: volumetric flow rate = 10m^3/s, t1= 20 C, 2nd inlet: volumetric flow rate = 30m^3/s, t2= 30C. At the outlet: t3= 55C, cross section area = 2m^2. Assume the effects of kinetic and potential energy are negligible and air behaves as a perfect gas iwth Cp= 1,0kJ/(kgK). Find the : mass flow rate at exit, heat rate of electric heater and exite velocity of air.

Homework Equations

The Attempt at a Solution

:
m1+m2=m3
Q-W= m1*ht1 + m2*ht2 - m3*ht3
W=0
Q=m1ht1+m2ht2-(m1+m2)ht3
m=A*ro*velocity[/B]
This looks OK so far, except for the signs of the right hand side...they are all opposite to what they should be. Please show some more detail.
 
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