What is the Mass of Air in a Cylindrical Column as a Function of Height?

AI Thread Summary
The discussion focuses on calculating the mass of air in a cylindrical column as a function of height, given the exponential decrease in air density with height. The density formula is provided as ρ = ρ0e−z/H, with ρ0 at 1.3 kg/m3 and H at 10 km. Participants discuss the need to integrate the density function from 0 to z to determine the mass, with some confusion about the integration process, particularly regarding the exponential term. Integration by substitution is suggested as a method to solve the integral, although detailed explanations are not provided. The conversation highlights the importance of correctly setting up the integral for accurate mass calculation.
~Sam~
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Homework Statement


The density of air in the lower atmosphere decreases exponentially with height: ρ = ρ0e−z/H
where ρ0 = 1.3 kg/m3 and H = 10 km. What is the mass of air in a cylindrical column of cross-sectional area 1 m2 and height z, as a function of z? How much mass is contained in such a column 1.0 km high?



Homework Equations



Volume of a Cylinder= pi*r*h


The Attempt at a Solution



I think I need to integrate from 0 to z to get the formula for mass. However, I'm not sure what the equation is that I need to integrate. I was thinking it might be something like intg[0,z] pi*r2e-z/Hρ0dz. Still if it that was, I see an issue with integrating e-z/H. I haven't gone to the second part because I need to know the first.
 
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Looks good to me.

m=\int^{z}_{0}dm=\int^{z}_{0}\pi r^{2}e^{-z/H}\rho_{0}dz

of course a mathematician will tell you that integrating for 0 to z is bad notation but its unlikely to give you the wrong answer.
 
How would you integrate e-z/h?
 
By substitution for the argument of the exponential.
 
Phyisab**** said:
By substitution for the argument of the exponential.

I'm not quite sure what you mean. Do you integration by substitution? Could you elaborate or give an example?
 
Yes integration by substitution. Its a pretty elementary integration, look in a calculus book. Sorry I don't have time right now to explain.
 
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