What is the mass of block on the left?

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The discussion revolves around calculating the mass of a block in a physics problem involving a 100kg block that takes 6.6 seconds to reach the floor. Participants use kinematic equations and Newton's second law (F=ma) to derive the acceleration and relate the masses in the system. After several attempts, the correct approach involves manipulating the equation to express the total mass in terms of the unknown smaller mass. Ultimately, the calculated mass of the smaller block is approximately 99.067kg. The conversation highlights the importance of systematic problem-solving in physics.
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Homework Statement



The 100kg block in the figure below takes 6.6s to reach the floor after being released from rest. What is the mass of block on the left?

http://i241.photobucket.com/albums/ff4/alg5045/p8-33.gif

Homework Equations



F=ma
kinematic equation

The Attempt at a Solution



I tried using accleeration = velocity/time, and I got .023 m/s^2. Then I used velocity = displacement/time, and I got .152 m/s. And then I got completely lost.
 
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You should be using
d = 0.5at^2 (assuming that initial v is 0)

so get a, and then
you know the system is moving with a

therefore weight of larger mass - wieght of smaller mass = (total mass)*a
 
Ok, for the acceleration I got .046m/s^2. How do I figure out what the total mass is since I don't know the smaller mass?
 
aligass2004 said:
Ok, for the acceleration I got .046m/s^2. How do I figure out what the total mass is since I don't know the smaller mass?

you want to solve for the smaller mass... write the total mass in terms of the smaller mass...
 
So larger mass-smaller mass = (larger mass + smaller mass)a
 
aligass2004 said:
So larger mass-smaller mass = (larger mass + smaller mass)a

(larger mass)*g - (smaller mass)*g = (larger mass + smaller mass)a
 
Got it after three tries at manipulating the equation. 99.067kg.
 
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