What Is the Mass Percent Concentration of CaCl₂ in the Solution?

AI Thread Summary
The discussion focuses on calculating the mass percent concentration of CaCl₂ in an aqueous solution using vapor pressure data. The vapor pressure of the solution is 80.8 mmHg, while pure water's vapor pressure at 50°C is 92.6 mmHg. Participants reference Raoult's law to relate the vapor pressures and mole fractions of the components. There is a reminder that CaCl₂ dissociates in solution, which affects the calculations. The conversation concludes with an acknowledgment of the need to consider these factors in solving the problem.
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% by mass concentration

Homework Statement



An aqueous CaCL2 solution has a vapor pressure of 80.8mmHG at 50 degree C . The vapor pressure of pure water at this temperature is 92.6 mmHG .

What is the concentration of CaCl2 in mass percent?

Homework Equations



% by mass = mass solute/mass solution.

The Attempt at a Solution



I tried converting the pressure into moles then dividing the moles of CaCl2 by the total moles. I am pretty stuck..

Thanks
Skadoo!
 
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Do you know Raoult's law?
 


yeah i do. p = pa*xa+pb*xb correct? not sure how to solve for the x's...
 


xa+xb=1
 


alright knowing this, i use 'a' as the vap press for cacl2 and 'b' for vap press of water? then use molecular weights to to solve for total mass of solution..?
 


Sounds OK. Don't forget CaCl2 is dissociated.
 


ah right, almost forgot. Ill give this a run thanks.
 
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