What Is the Maximum Angular Momentum of a Particle Moving Past a Point?

AI Thread Summary
The discussion centers on determining the maximum angular momentum of a particle moving past a point O, with given parameters of mass, velocity, and minimum distance. Participants clarify that angular momentum is maximized when the particle's motion is perpendicular to the radius vector from point O. Despite initial confusion suggesting zero angular momentum, it is established that the distance of 2 m from the line ensures a non-zero value. The correct formula relating angular momentum to mass, velocity, and radius is emphasized as essential for solving the problem. Ultimately, the maximum angular momentum cannot be zero due to the specified distance from point O.
dinonichas
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Homework Statement



A particle moves in a straight line past a point O, as shown below. At which point is the angular momentum maximum (with respect to O)? If the minimum distance between O and the line is 2 m, and the object has a mass of 2 kg and a velocity of 3 m/s, what is the maximum angular momentum of the particle with respect to O?


Homework Equations



angular momentum is equal to:
Iω= (mr^2)mv ??

The Attempt at a Solution



0,i think,because the momentum should be 90 degree from the radius to make the angular momentum.so in this case the particle is moving in the straight line with the point O so it will be 0
 
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dinonichas said:
angular momentum is equal to:
Iω= (mr^2)mv ??

\omega \neq mv

There is a simple formula relating angular momentum to mass, velocity, and radius vector. Find that formula in your textbook and use it.

the momentum should be 90 degree from the radius to make the angular momentum.

This is correct.

so in this case the particle is moving in the straight line with the point O so it will be 0

But this isn't. If the point O is 2 m from the line, the angular momentum (with respect to that point) can't be zero.
 
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