What Is the Maximum Force Before the Top Block Slides Off?

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The discussion revolves around calculating the maximum force that can be applied to a system of three blocks before the top block (3M) slides off. The blocks are arranged with M and 2M side by side on a frictionless surface, while 3M is placed on top of 2M, which has friction with it. The applied force is 28 N, and the coefficients of static and kinetic friction between the blocks are μs = 0.26 and μk = 0.15. The correct answer for the maximum force before sliding occurs is determined to be 107 N. The user seeks assistance in understanding the calculations leading to this result.
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Three blocks (M, 2M, and 3M) are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box of mass M. There is friction between the surfaces of blocks 2M and 3M (μs = 0.26, μk = 0.15) so the three blocks accelerated together to the right.
The blocks are set up so that M and 2M are side by side with 3M on top of 2M.
M = 7 kg
F = 28 N

I tried using basic kinematic and friction equations, but haven't been able to get the correct answer which is 107 N. Help is greatly appreciated.
 
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Just realized I hadn't posted the actual question:
What is the maximum force F that can be applied, before the 3M block slides off?
 

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