What Is the Maximum Force to Move Two Stacked Blocks Together?

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SUMMARY

The discussion centers on the physics problem involving two stacked blocks, where a force of at least 12N is required to overcome static friction and initiate movement of the top block. The blocks are analyzed on a frictionless table, leading to two key calculations: the maximum horizontal force that can be applied to the lower block without causing the top block to slip, and the resulting acceleration of both blocks. The static friction force is determined to be 12N, allowing for the calculation of the coefficient of static friction.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Familiarity with basic physics concepts such as mass and force
  • Ability to perform calculations involving force and acceleration
NEXT STEPS
  • Calculate the maximum horizontal force using the formula F = μs * N
  • Determine the acceleration of the blocks using Newton's second law, F = ma
  • Explore the differences between static and kinetic friction coefficients
  • Study real-world applications of friction in mechanics
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of friction and motion in mechanics.

theunloved
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A block of mass m1 = 4 kg is put on top of a block of mass m2 = 5 kg. To cause the top block to slip on the bottom one while the bottom one is held fixed, a horizontal force of at least 12N must be applied to the top block. The assembly of blocks is now placed on a horizontal, frictionless table. Find the magnitude of
a. The max. horizontal force F that can be applied to the lower block so that the block will move together
b. The resulting acceleration of the blocks.

Ok, so I'm not here to ask for how to do it, not yet ;). I'm here to ask if anyone here could explain the problem to me, especially the one that is bold. I have no idea what they are talking about...Thanks
 
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If I understood it corretly, it basically means this:

the minimum force applied to the block in order to "win" against static friction - which is holding the block in its place - is 12N.
To help visualize things: just forget about the bottom block.
Pretend the block you want to move is on the ground. Can you understand why the minimum force is 12N?
 
U.Renko said:
If I understood it corretly, it basically means this:

the minimum force applied to the block in order to "win" against static friction - which is holding the block in its place - is 12N.
To help visualize things: just forget about the bottom block.
Pretend the block you want to move is on the ground. Can you understand why the minimum force is 12N?

Yes, now I got it, so basically if it's put on the ground, 12N is the minimum force that you need to apply in order to move it. So fs maximum will be 12 N, right ? and since we have fs = us * mg = 12N, we could find coefficient of static friction...uhm, or coefficient of kinetic friction ? wasn't it called uk when its moving and us when its not ? I got confused again... :(((
 

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