What Is the Maximum Force to Move Two Stacked Blocks Together?

AI Thread Summary
To move two stacked blocks together, a minimum horizontal force of 12N must be applied to the top block to overcome static friction. This force is necessary to initiate movement, as it represents the maximum static friction force acting on the top block. When considering the blocks on a frictionless table, the maximum force applied to the lower block should not exceed this static friction limit to ensure both blocks move together. The resulting acceleration can be calculated using Newton's second law, factoring in the total mass of both blocks. Understanding the distinction between static and kinetic friction coefficients is crucial for solving related problems.
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A block of mass m1 = 4 kg is put on top of a block of mass m2 = 5 kg. To cause the top block to slip on the bottom one while the bottom one is held fixed, a horizontal force of at least 12N must be applied to the top block. The assembly of blocks is now placed on a horizontal, frictionless table. Find the magnitude of
a. The max. horizontal force F that can be applied to the lower block so that the block will move together
b. The resulting acceleration of the blocks.

Ok, so I'm not here to ask for how to do it, not yet ;). I'm here to ask if anyone here could explain the problem to me, especially the one that is bold. I have no idea what they are talking about...Thanks
 
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If I understood it corretly, it basically means this:

the minimum force applied to the block in order to "win" against static friction - which is holding the block in its place - is 12N.
To help visualize things: just forget about the bottom block.
Pretend the block you want to move is on the ground. Can you understand why the minimum force is 12N?
 
U.Renko said:
If I understood it corretly, it basically means this:

the minimum force applied to the block in order to "win" against static friction - which is holding the block in its place - is 12N.
To help visualize things: just forget about the bottom block.
Pretend the block you want to move is on the ground. Can you understand why the minimum force is 12N?

Yes, now I got it, so basically if it's put on the ground, 12N is the minimum force that you need to apply in order to move it. So fs maximum will be 12 N, right ? and since we have fs = us * mg = 12N, we could find coefficient of static friction...uhm, or coefficient of kinetic friction ? wasn't it called uk when its moving and us when its not ? I got confused again... :(((
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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